-10x^2+45x-45=0

Solution for -10x^2+45x-45=0 equation:

-10x^2+45x-45=0

a = -10; b = 45; c = -45;
Δ = b2-4ac
Δ = 452-4·(-10)·(-45)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-15}{2*-10}=\frac{-60}{-20}
=+3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+15}{2*-10}=\frac{-30}{-20}
=1+1/2
$